Question

value of n the end terms of 60,62,64

Answer 1

d=t2-t1
$d = 62 - 60 \\ d = 2$
Now
FIRST TERM(a)=60
COMMON DIFFERENCE(d)=2
${n}^{th} \: \: term \: \: of \: \: ap \\ t_{n} = a + (n - 1)d \\ t_{n} = 60 + (n - 1)2 \\ t_{n} = 60 + 2n - 2 \\ t_{n} = 58 + 2n$