Math, asked by yadavrajesh4983, 7 months ago

value of p= -5/11 4(3p+2)-5(6p-1)=2(p-8)-6(7p-4) variable

Answers

Answered by bhoomika111141
1

Answer:

Given :4(3p + 2) -5(6p -1) = 2(p - 8) -6(7p - 4)4(3p+2)−5(6p−1)=2(p−8)−6(7p−4)

To Find : Value of p

Solution:

4(3p + 2) -5(6p -1) = 2(p - 8) -6(7p - 4)4(3p+2)−5(6p−1)=2(p−8)−6(7p−4)

12p + 8 -30p +5 = 2p - 16-42p +2412p+8−30p+5=2p−16−42p+24

13-18p =-40p +813−18p=−40p+8

13-8 =-40p +18p13−8=−40p+18p

5 =-22p5=−22p

\frac{-5}{22}=p22−5=p

So, The value of p is \frac{-5}{22}22−5

Step-by-step explanation:

MARK AS BRAINLIEST AND FOLLOW

Similar questions