Math, asked by BHAWESH111, 1 year ago

value of 'p' for which (x^2+3x+p) divisible by (x-2)is

Answers

Answered by mysticd
66

Answer:

\red { Value \: of \: p } \green {= -10}

Step-by-step explanation:

 Let \:p(x) = x^{2}+3x+p

 If \: p(x) \:is \: divisible \: (x-2) \:then \: the \\remainder \: p(2) = 0

/*

Factor theorem :

If (x-a) is a factor of the polyomial p(x), then

p(a) = 0 . */

 p(2) = 0

\implies 2^{2} + 3\times 2 + p = 0

\implies 4 + 6 + p = 0

\implies 10 + p = 0

 \implies p = -10

Therefore.,

\red { Value \: of \: p } \green {= -10}

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Answered by AkshitaFeb
20

It is divisible by - 10 hence , Value of p = - 10

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