Question

value of potential difference | Va - Vb | shown in figure is how much volt ?​

Answer 1

Explanation:

equivalent capacitance ,C =( c x c) /2c = c/2

pd across the terminal A and B is 40V

Q = C x 40 = c/2 x 40 = 20c

Va - Vb = Q / c = 20c /c = 20V.

Answer 2

The value of potential difference is 20 V

Explanation:

Given:

In the circuit a 40 V battery is connected with two capacitors as shown

To find out:

The Potential difference between A and B

Soluton:

Let the capacitance be C

First we need to find out the value of C

For this we must calculate equivalent capacitance

The capacitors are connected in series

We know that if two cpacitors are connected in series, the equivalent capacitance C is

$\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}$

Thus,

$\frac{1}{C'}=\frac{1}{C}+\frac{1}{C}$

$\implies \frac{1}{C'}=\frac{2}{C}$

$\implies C'=\frac{C}{2}$

Also we know that

$Q=CV$

Where Q is the charge flown through the battery

Thus,

$Q=\frac{C}{2}\times 40$

$\implies Q=20C$

The same charge will flow through the first capacitor

Thus, the potential drop between A and B

$|V_A-V_B|=\frac{Q}{C}$

$\implies |V_A-V_B|=\frac{20C}{C}$

$\implies |V_A-V_B|=20$ V

Hope this answer is helpful.

Know More:

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