Value of ‘s’ in (1 / 5) + (2s / 5) = (2 / 5) + (s / 5) is
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Answered by
3
Answer:
s=1
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Answered by
2
Answer:
As we can also write it as,
1/( s² + 4s + 5) = 1/{ (s + 2)² + 1 }
As we all know that,
L-¹{ a/(s²+a²) } = sin at
L-¹{ f(s+a) } = e^(-a) * F(s)
So,
L-¹{ 1/{ (s + 2)² + 1 } } = e^(-2) * sin t.
Hope it may help you.)
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