Question

Value of sec^20 - cot^2
(90° – 0) is .............​

Answer 1

find sec^2 theta - cot^2 (90-theta) Without using trigonometric tables, prove that : sec2 (90 - theta) - cot2theta / 2( sin2 25 + sin2 65 ) + 2 cos2 60 tan2 28 tan2 62 / 3( sec2 43 - cot2 47 ) = 2/3 . The Brainliest Answer!

Answer 2

Answer: ans=1

Step-by-step explanation:

sec^2O-cot^2(90-O)

sec^2O -tan^2O

=1 (by identity sec^2A-tan^2A=1)