Question

value of sec a when value of tan a is 5/12​

Answer 1

Answer:

Answer:tan a=5/12

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,Hypotenuse = √(5^2+12^2)

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,Hypotenuse = √(5^2+12^2) √(25 + 144)

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,Hypotenuse = √(5^2+12^2) √(25 + 144) √169

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,Hypotenuse = √(5^2+12^2) √(25 + 144) √169 13

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,Hypotenuse = √(5^2+12^2) √(25 + 144) √169 13sec alpha =1/cos alpha=hypotenuse/adjacent side=13/12

Answer:tan a=5/12from trig ratio [triangle] Tan alpha =opposite side / Adjacent side = 5/12hence,Hypotenuse = √(5^2+12^2) √(25 + 144) √169 13sec alpha =1/cos alpha=hypotenuse/adjacent side=13/12sec alpha =13/12

Step-by-step explanation:

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Answer 2

Answer:

sec a = 13/12

Step-by-step explanation:

Sec^2 a = tan^2 a + 1

= (5/12)^2 + 1

= 25/144 + 1

=25+144/144 + 1 [On taking lcm]

=169/144

Sec^2 a =(13/12)^2

Sec a = 13/12