Question

value of sec
sec^2 26 - cot^2 64
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Answer 1

$\red{ \ Answer}$

${ \cot}^{2} 64 = { \tan}^{2} (90 - 64) ={ \tan }^{2} (26)$

Using this value above,

${ \sec}^{2} 26 - { \tan }^{2} 26$

Using identity,

${ \sec}^{2} \alpha - { \tan }^{2} \alpha = 1$

Gives the answer as 1.

$\red{ \ hope \ it's \ helps \ you}$