Question

value of sin^-1(-1/2)=?​

Answer 1

Answer:

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Answer 2

$\huge\dag\underline\mathbb\red{SoLuTiOn}\dag$

Let

${sin}^{ - 1} ( \frac{ - 1}{2} ) = y \: \: then \: \: , sin \: \: y = \frac{ - 1}{2}$

Range of principal value for

${sin}^{ - 1} \: \: is \: \: [ \frac{ - \pi}{2} \: \: , \: \: \frac{\pi}{2} ] \: \: and \: \: sin \: \: ( \frac{ - \pi}{6} )= \frac{ - 1}{2} .$

Therefore, principal value of

${sin}^{ - 1} ( \frac{ - 1}{2} ) = \frac{ - \pi}{6}$