value of sin 1 by 3 + s equal 2 by 5 a number 4 by 5
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We have
2sin
−1
x+3sin
−1
y=
2
5π
.............(i)
and y=kx−5............(ii)
We know sin
−1
xϵ[−
2
π
,
2
π
] for xϵ[−1,1]
max value of sin
−1
x is
2
π
So let
x=1
y=1 then
2.
2
π
+
2
3π
=
2
5π
Duration will hold only for x=1
y=1
put x=1 and y=1, we get
1=k−5⇒k=6
option (c)
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