Question

value of sin 12 degree minus Cos 78 degree + secant squared theta minus cot square into 90 minus theta​

Answer 1

Answer:

$\sin(12) - \cos(78) + { \sec \ }^{2} \alpha - \\ { \cot}^{2} (90 - \alpha )$

$\sin(12 ) - \cos(90 - 12) + { \sec}^{2} \alpha - \\ { \tan \: }^{2} \alpha$

$\sin(12) - \sin(12 ) + 1$

=1

hope it helps you .

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here , alpha is used instead of theta