Question

value of sin 15 °

Calculate​

Answer 1

$\huge\star{\tt{\underline{\underline{\red{Answer}}}}}\star$

$\huge{\boxed{\boxed{\mathbb{\blue{Sin \: 15°}}}}}$

sin(A-B)= SinACosB-CosASinB

Sin15°=Sin(45-30)

$\implies$ Sin45Cos30 - Cos45Sin30

$\implies$ $\large{\frac{1}{\sqrt{2}}}$$\large{\frac{\sqrt{3}}{2}}$ - $\large{\frac{1}{\sqrt{2}}}$$\large{\frac{1}{2}}$

$\implies$ $\large{\frac{\sqrt{3}}{2\sqrt{2}}}$-$\large{\frac{1}{2\sqrt{2}}}$

$\implies$$\large{\frac{\sqrt{3} -1}{2\sqrt{2}}}$

Answer 2

Answer:

here's the answer ll

hope it helps you