Math, asked by aasthapatel82911, 9 months ago

Value of sin^2 30° - cos^30°

Answers

Answered by sarkarharsh708
3

Answer:

-1/2

Step-by-step explanation:

sin²30° - cos²30°

= (1/2)² - (√3/2)²

= 1/4 - 3/4

= -2/4

= -1/2

Answered by Anonymous
19

Correct Question :

Find the value of

Sin² 30° -cos² 30°

\red{\huge{\boxed{\sf{Solution:}}}}

Let's look at some values

\begin{array}{| c | c | c | c | c | c |}\cline{1-6} \bf Angles & \bf 0^{o} & \bf 30^{o} & \bf 45^{o} & \bf 60^{o} & \bf 90^{o} \\\cline{1-6} \tt Sin \theta & 0 & \dfrac{1}{2} & \dfrac{1}{\sqrt{2}}& \dfrac{\sqrt{3}}{2}& 1\\\cline{1-6} \tt cos \theta & 1 & \dfrac{\sqrt{3}}{2} &\dfrac{1}{\sqrt{2}}&\dfrac{1}{2}&0\\\cline{1-6} \tt tan \theta & 0 & \dfrac{1}{\sqrt{3}} & 1& \sqrt{3} & \infty \\\cline{1-6} \tt cosec \theta & \infty & 2 & \sqrt{2} & \dfrac{2}{\sqrt{3}} &1\\\cline{1-6} \tt sec \theta & 1 & \dfrac{2}{\sqrt{3}} & \sqrt{2} & 2 & \infty \\\cline{1-6} \tt cot \theta & \infty & \sqrt{3} &1& \dfrac{1}{\sqrt{3}} &0\\\cline{1-6}\end{array}

Here, '\red{\infty}' stands for

undefined(not defined) values.

\rule{200}2

\sf\sin{}^{2}30\degree-\cos{}^{2}30\degree

\sf=(\dfrac{1}{2})^2-(\dfrac{\sqrt{3}}{2})^2

\sf=\dfrac{1}{4}-\dfrac{3}{4}

\sf=\dfrac{\cancel{-2}}{\cancel{4}}

\sf=\dfrac{-1}{2}

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