Question

Value of sin(37^circ)cos(53^circ) is

Answer 1

I think your question is wrong.

plz check it again.

Answer 2

$\huge\underline\mathfrak{Question:-}$

Value of sin(37^circ)cos(53^circ) is

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sin(37°).cos(53°)

FIRST METHOD:-

=sin(90–53).cos 53°

=cos 53°. cos53°

=cos^2(53°). Answer.

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SECOND METHOD:-

=sin37.cos(90°-37°)

=sin37°.sin37°

=sin^2(37°). Answer.

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THIRD METHOD:-

= 1/2.[ 2.sin37.cos 53 ]

=1/2.[sin(37+53)+sin(37–53)]

=1/2.[sin90° - sin 16° ].

= 1/2.[1 - sin 16°].

= 1/2.[sin^2 (8°) +cos^2 (8°)-2.sin8°.cod 8°].

= 1/2.(sin 8°-cos 8°)^2.Answer.

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