Question

value of sin(45°+theta) cos(15°+theta) - cos(45°+theta) sin (15°+theta)​

Answer 1

Answer:

1/2

Explanation:

$we \: know \: that \\ sin( \alpha - \beta ) = \sin( \alpha ) \cos( \beta ) - \cos( \alpha ) \sin( \beta ) \\ so \\ sin( {45}^{o} + \theta) cos( {15}^{o} + \theta) - cos( {45}^{o} + \theta) sin( {15}^{o} + \theta) \\ = \sin( {45}^{o} + \theta - {15}^{o} - \theta ) \\ = \sin( {30}^{o} ) \\ = \frac{1}{2}$