Question

value of sin(60°+Q)-cos(30°-Q)is...​

Answer 1

Answer:

sin(60°+Q) - cos(30°-Q)

= sin(60°+Q) - sin{90°-(30°-Q)}

= sin(60°+Q) - sin{90°-30°+Q}

= sin(60°+Q) - sin(60°+Q)

= 0

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