Question

value of (sin24°+cos6°)​

Answer 1

Answer:

We know that,

(1)sin(90∘−x)=sin(π2−x)=cosx

(2)cos(90∘−x)=cos(π2−x)=sinx

(3)sinAcosB−cosAsinB=sin(A−B)

We take,

X=sin24°cos6°−sin6°sin66°sin21°cos39°−cos51°sin69°

using:(1)and(2)

sin66∘=sin(90∘−24∘)=cos24∘

cos51∘=cos(90∘−39∘)=sin39∘

sin69∘=sin(90∘−21

Explanation:

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