value of tan 2A, if cos3A =sin45'
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Hey !!
cos3A = sin45°
sin ( 90° - 3A ) = sin 45°
90 ° - 3A = 45°
3A = 45
A = 15°
AND tan2A = tan2× 15° = tan30°
=> 1/√3 Answer
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Hope it helps you !!!
@Rajukumar111
cos3A = sin45°
sin ( 90° - 3A ) = sin 45°
90 ° - 3A = 45°
3A = 45
A = 15°
AND tan2A = tan2× 15° = tan30°
=> 1/√3 Answer
****************************
Hope it helps you !!!
@Rajukumar111
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