Math, asked by Musicalsinging, 19 days ago

value of tan 60-45 sin18​

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Answered by aratisikdar7
0

Step-by-step explanation:

tan 60-45 sin18

= √3-(45×cos30)

=√3-(45×√3/2)

 \sqrt{3} -  \frac{45 \sqrt{3} }{2}

 \frac{2 \sqrt{3}   -  45 \sqrt{3} }{2}  \\  =  \frac{ - 43\sqrt{3} }{2} ans

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