Question

value of [tan A + 1/cos A]^2 + [tan A - 1/cos A]^2
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Answer 1

Answer:

(tan A + 1/cos A) ^2 + (tan A - 1 /cos A) ^2

= tan A^2 + 1/cos A ^2 + tan A^2 - 1/cos A ^2

= tan A^2 + sec A^2 + tan A^2 - sec A^2

(tanA^2 - 1 = secA^2 )

= (tanA + secA)^2 + (tanA - secA)^2

= tanA^2 + secA^2 + 2tanA.secA + tanA^2 + sec^2 + 2tanA.secA

= 2tanA^2 +2secA^2

= 2(tanA^2 + secA^2 )

= 2 (sinA^2/cosA^2 + 1/cosA^2)

= 2 ( sin+ sinA^2/ cosA^2)

hopefully, this is correct.

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