value of tan35°÷cot 55°+cot 78°÷ tan 12°
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Given,
cot55otan35o+tan12ocot78o
=cot(90o−35o)tan35o+tan(90o−78)cot78o
=tan35otan35o+cot78ocot78o as we know cot(90o−θ)=tanθ and tan(90o−θ)=cotθ
=1+1
=2
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Answer:
here answer is 2 for this question
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