Math, asked by bsahasra2020, 4 months ago

value of tan35°÷cot 55°+cot 78°÷ tan 12°

Answers

Answered by ujjwal26200

0

Given,

cot55otan35o+tan12ocot78o

=cot(90o−35o)tan35o+tan(90o−78)cot78o

=tan35otan35o+cot78ocot78o as we know cot(90o−θ)=tanθ and tan(90o−θ)=cotθ

=1+1

=2

Answered by bvarun2009

0

Answer:

here answer is 2 for this question

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