Question

value of tan35°÷cot 55°+cot 78°÷ tan 12°​

Answer 1

Given,

cot55otan35o+tan12ocot78o

=cot(90o−35o)tan35o+tan(90o−78)cot78o

=tan35otan35o+cot78ocot78o  as we know cot(90o−θ)=tanθ and  tan(90o−θ)=cotθ

=1+1

=2

Answer 2

Answer:

here answer is 2 for this question