Question

Value of $\frac{x^3}{6}+\frac{Cx^2}{2}+Cx+C$

TrickY question

Answer 1

$\frac{x^3}{6}+\frac{Cx^2}{2}+Cx+C=\frac{x^3+3Cx^2+6Cx+6C}{6}$

$Steps$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:Cx=\frac{Cx}{1},\:C=\frac{C}{1}$

$=\frac{x^3}{6}+\frac{Cx^2}{2}+\frac{Cx}{1}+\frac{C}{1}$

$\mathrm{Least\:Common\:Multiplier\:of\:}6,\:2,\:1,\:1:\quad 6$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$=\frac{x^3}{6}+\frac{Cx^2\cdot \:3}{6}+\frac{Cx\cdot \:6}{6}+\frac{C\cdot \:6}{6}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{x^3+Cx^2\cdot \:3+Cx\cdot \:6+C\cdot \:6}{6}$

Answer 2

I hope this answer in figure helps you.