Question

value of
$log_{2}(16) + log_{3}(81)$
​

Answer 1

Answer:

$log_{2}(16) + log_{3}(81) = 4$

Step-by-step explanation:

$log_{2}(16) + log_{3}(81) \\ = log_{2}( {2}^{4} ) + log_{3}( {3}^{4} ) \\ = 4 log_{2}(2) + 4log_{3}(3) \\ = 4 + 4 \\ = 8$

Answer 2

Answer:

The solution would be...