Question

value of
$\tan {}^{2} - \frac{6}{ \cos {}^{2} }$
​

Answer 1

$\frac{ { \sin(x) }^{2} }{ { \cos(x) }^{2} } + - \frac{6}{ { \cos(x) }^{2} } \\ \frac{ { \sin( x) }^{2} - 6 }{ { \cos(x) }^{2} }$

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