Value of the expression root 3 cosec 20 - sec 20 = ?
Answers
Answered by
25
HEY DEAR ... ✌
____________________________
= sqrt(3)/ sin 20 - 1/cos 20
= (sqrt(3) cos 20 - sin 20))/ ( sin 20 cos 20)
= 2( sqrt(3)/2 cos 20 - (1/2) sin 20/ ( sin 20 cos 20)
= 4 ( cos 30 cos 20 - sin 30 sin 20)/ ( 2 sin 20 cos 20)
= 4 (cos (30+20))/ sin 40
= 4 cos 50/cos 50
= 4
HOPE , IT HELPS ... ✌
____________________________
= sqrt(3)/ sin 20 - 1/cos 20
= (sqrt(3) cos 20 - sin 20))/ ( sin 20 cos 20)
= 2( sqrt(3)/2 cos 20 - (1/2) sin 20/ ( sin 20 cos 20)
= 4 ( cos 30 cos 20 - sin 30 sin 20)/ ( 2 sin 20 cos 20)
= 4 (cos (30+20))/ sin 40
= 4 cos 50/cos 50
= 4
HOPE , IT HELPS ... ✌
Similar questions