Question

Value of the roots of the quadratic equation x^2-x-6=0

Answer 1

Answer:

x²-x-6 =0

x²-(3-2)x-6=0

x²-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x=3,-2

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Answer 2

Answer:

x^2 - x - 6

= x^2 -3x +2x - 6

= x(x-3) +2(x-3)

0 = (x-3) (x+2(

x-3 = 0 x+2 = 0

x = +3 x = -2

Step-by-step explanation:

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