Math, asked by kuldeepthakur180, 11 months ago

value of the roots of the quadratic equation,x^2-x-6=0 are _____.​

Answers

Answered by sweett2314
1

Answer:

x=2 x=-3

Step-by-step explanation:

Factoring x2-x-6

The first term is, x2 its coefficient is 1 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 .

-6 + 1 = -5

-3 + 2 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2

x2 - 3x + 2x - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-3)

Add up the last 2 terms, pulling out common factors :

2 • (x-3)

Step-5 : Add up the four terms of step 4 :

(x+2) • (x-3)

Which is the desired factorization

Equation at the end of step 1 :

(x + 2) • (x - 3) = 0

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