Question

Value of the roots of the quadratic equation, x2-x-6=0are
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Answer 1

Answer:

The roots are 3 and -2.

Step-by-step explanation:

The formula to compute roots of a quadratic equation ax² + bx + c = 0 is:

$x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }$

Here:

a = 1

b = -1

c = -6

Compute the roots as follows:

$x = \frac{ -(-1) \pm \sqrt{(-1)^2 - 4(1)(-6)}}{ 2(1) }\\x = \frac{ 1 \pm \sqrt{1 - -24}}{ 2 }\\x = \frac{ 1 \pm \sqrt{25}}{ 2 }\\x = \frac{ 1 \pm 5\, }{ 2 }\\x = \frac{ 6 }{ 2 } \; \; \; x = -\frac{ 4 }{ 2 }\\x = 3, -2$

Thus, the roots are 3 and -2.

Answer 2

Answer:

x= -2 or x=3

Step-by-step explanation:

x2-x-6=0

x^2+2x-3x-6=0

(x+2)(x-3)=0

x= -2 or x=3

THIS IS BY FACTORISATION METHOD.