Chemistry, asked by Shinushree7533, 1 year ago

Value of vant hoff factor i for weak binary electrolyte having 40% dissociation is

Answers

Answered by shriharikrishna007
1

Answer:

Solution : Given,

Degree of dissociation of binary electrolyte =  = 40% = 0.40

Binary electrolyte : It is the electrolyte molecule that dissociates into two ions in a solution. For example : NaCl, KCl etc.

The general equilibrium reaction will be,

                                  

Initial moles               1       0     0

After association           

The total number of moles after dissociation =

Formula of Van't Hoff factor :

Now put the value of alpha in this expression, we get :

Therefore, the Van't Hoff factor will be, 1.4

Answered by seenuseenu20
0

Answer:

Given,

Degree of dissociation of binary electrolyte =  = 40% = 0.40

Explanation:

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