Math, asked by jawalenihal2006, 6 months ago

value of x (3/5)³*(3/5)^-6=(3/5)^2x-1​

Answers

Answered by manojkumarj
1

Answer:

Step-by-step explanation:

(3/5)³ × (3/5)^-6 = (3/5)^2x-1

(3/5)^3+(-6) = (3/5)^2x-1

(a^m×aⁿ = a^m+n)

Bases are equal. Exponents must be equal.

3+(-6) = 2x-1

3-6 = 2x-1

-3 = 2x-1

2x = -3+1

2x = -2

x = -2/2

x = -1

Hope it helps

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