Question

Value of x^3+y^3+z^3-3xyz,for x= -3,y= -2,z=5 is: *

Answer 1

Answer:

0

Step-by-step explanation:

x^ 3+ y^3+ z^3- 3xyz =( x^2 + y^2 + z^2 - xy - yz - zx)

now, x = -3

y=-2

z=5

so,on substituting values of x y and z we get:

(-3+-2+5 )(x^2 + y^2 + z^2 - xy - yz - zx)

=0(x^2 + y^2 + z^2 - xy - yz - zx)

=0.