Question

value of X and Y which is in figure ​

Answer 1

$<marquee behaviour=move by color=pink><h1>Hola ✋✋</h1></marquee>$

Given,

AD=DC

So, /_DCA=32°

Thus, x=32+32=64°(Exterior angle theorem)

Now,

CD=CB

So,

/_DBC=x=64°

x+x+y=180°(Angle sum property)

Substituting x=64°

64°+64°+y=180

y=180°-128°=52°

Thus,

$\boxed{x=64°}$

$\boxed{y=52°}$

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Answer 2

Answer

In the picture. Hope it helps...