Question

Value of x for which the numbers (5x+2), (4x -6) and (x+2) are in AP, is

Answer 1

Given :

• AP :- (5x+2), (4x -6) ,(x+2)

To find :

• the value of x

Concept used :

• 2b = a+c

where :-

• b = second term
• a = first term
• c = third term

Solution :

Given AP is (5x+2), (4x -6) ,(x+2)

We know that :- 2b = a+c

Now put :-

• b = 4x -6

• a = 5x+2

• c = x+2

⟹ 2(4x -6)= 5x+2+x+2

⟹ 8x - 12= 6x + 4

⟹ 8x - 6x = 12 + 4

⟹ 2x = 16

⟹ x = 16/2

⟹ x = 8

Answer :

The value of x = 8

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Learn more :-

1. Tn = a+(n-1)d

2. Sn = n/2[2a+(n-1)d]

3. Sn = n/2(a+l)

4. d = b-a

where:-

• a = first term
• n = number of terms
• d = common difference
• Tn = nth term
• l = last term
• d = common difference
• b = second term

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