Question

value of x if 4(sec square59-cot square31/3) - 2/3sin90 + 3 tan square 56 * tan square 34 =x/3

Answer 1

hope it will be useful to you

Answer 2

Answer:

$Value \: of \: x = 11$

Step-by-step explanation:

$4\left(\frac{sec^{2}59-cot^{2}31}{3}\right)-\frac{2}{3}sin90+3tan^{2}56\times tan^{2}34=\frac{x}{3}$

$\times 4\left(\frac{sec^{2}59-cot^{2}(90-59)}{3}\right)-\frac{2}{3}sin90+3tan^{2}56\times tan^{2}(90-56)=\frac{x}{3}$

$\implies 4\left(\frac{sec^{2}59-tan^{2}59}{3}\right)-\frac{2}{3}sin90+3tan^{2}56\times cot^{2}56=\frac{x}{3}$

$\implies 4\times \frac{1}{3}-\frac{2}{3}\times 1 +3\times 1 = \frac{x}{3}$

\* We know that,

i) sec²A-tan²A = 1

ii) tanAcotA = 1

iii) sin90° = 1 */

$\implies \frac{4-2+9}{3}=\frac{x}{3}$

$\implies \frac{11}{3}=\frac{x}{3}$

/*Multiply each term by 3, we get

$\implies 11=x$

Therefore,

$Value \: of \: x = 11$

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