Question

value of x in the quadratic equation x^2-20x+75=0 *​

Answer 1

Answer:

refer this................

Answer 2

Answer:

Step-by-step explanation:

Solving    x^2+20 x+75 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax^2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

x = -B+√B^2-4 AC/2 A,

In our case,  A   =     1

                     B   =    20

                     C   =   75

Accordingly,  B2  -  4AC   =

                    400 - 300 =

                    100

Applying the quadratic formula:

x= -20+√100/2,

Can  √ 100 be simplified ?

Yes!   The prime factorization of  100   is

  2•2•5•5  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 100   =  √ 2•2•5•5   =2•5•√ 1   =

               ±  10 • √ 1   =

               ±  10

So now we are looking at:

          x  =  ( -20 ± 10) / 2

Two real solutions:

x =(-20+√100)/2=-10+5= -5.000

or:

x =(-20-√100)/2=-10-5= -15.000

Two solutions were found :

1:x = -5

2:x = -15 .

Hope it helps you.