Question

Value of x satisfying the equation √x+4=x-2

Answer 1

answer hi 4 x ki place pe 4 put kro satisfy ho jayegi equation

Answer 2

Answer:

Step-by-step explanation:

$\sqrt{x+4}=x+2\\ x+4=(x+2)^{2} \\x+4=x^{2} +4x+4\\x^{2} +3x=0\\x(x+3)=0\\\\either</p><p>\\x=0\\\\or\\x+3=0\\x=-3\\\\so\\\\x=0,x=-3\\\\\\hope it helps$