Question

Value of x when 1 + 6 + 11 + 16 + ..... + x =
148 is​

Answer 1

Answer:

1 + 6 + 11 + 16 +.... + x = 148

34 + ...... + x = 148

... + x = 148 - 34

... + x = 114

so...for exact value of x we should know the number at blank place....

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Answer 2

Answer:

Answered

Find the value of X for AP 1+6+11+16+...+X=148

Let x be the n-th term of A.P.

Given : first term 1, common difference = 5, Sum of n terms 148.

Hence we have, (n/2) [ 2+(n-1)5 ] = 148

above eqn. is simplified as, 5n2 -3n -296 = 0

By factorising LHS, we write, (n-8)(5n+37) = 0

hence n, number of terms in A.P. = 8

x = 8th term = 1+(7)5 = 36

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