Question

value of x+y
from the given figure ​

Answer 1

Answer:

150°

Step-by-step explanation:

Given : angle CAB = 40°

To find : Value of x + y

Solution :

We know that, diagonals of a rectangle are equal and are bisected by each other.

→ AC = BD

→ 1/2 AC = 1/2 BD

→ AO = BO

→ CO = BO

(O is the point of intersection of the diagonals)

So, this means ∆ COB and ∆AOB are isosceles triangle.

→ angle OAB = angle OBA

→ angle OBA = 40°

Now, in ∆AOB, by angle sum property,

y + 40 + 40 = 180°

→ y = 180° - 80°

→ y = 100°

Now, angle CBA is 90° (since it's rectangle)

Also, angle OBA + angle OBC = angle CBA

→ 40 + angle OBC = 90°

→ 40 + x = 90

→ x = 50°

Hence, value of x + y = 50 + 100 = 150°

Answer 2

Answer:

thus x+y=100+50=150

hope it helps