Math, asked by saritaroutray1, 22 days ago

value of x-y^x-y
x=2
y=-2

Answers

Answered by simi20010111

1

Answer:

$x-y^x-y \\ = 2 - ( { - 2})^{2} - ( - 2) \\ = 2 - 4 + 2 \\ = 4 - 4 \\ = 0$

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