Question

value of (x2−2x/x2+2x)*(3x+6/x−2)

Answer 1

value of (x2−2x/x2+2x)*(3x+6/x−2) is as follows

Given,

$\dfrac{x^2-2x}{x^2+2x} \times \dfrac{3x+6}{x-2}\\\\=\dfrac{x(x-2)}{x(x+2)}\times \dfrac{3x+6}{x-2}\\\\\\=\dfrac{x-2}{x+2}\times \dfrac{3x+6}{x-2}\\\\\\=\dfrac{\left(x-2\right)\left(3x+6\right)}{\left(x+2\right)\left(x-2\right)}\\\\\\= \dfrac{3x+6}{x+2}\\\\\\=\dfrac{3\left(x+2\right)}{x+2}\\\\=3$

Therefore, the value of (x2−2x/x2+2x)*(3x+6/x−2) is  3.

Answer 2

Answer:

Hope it helps

Step-by-step explanation:

x

2

+2x

x

2

−2x

×

x−2

3x+6

=

x(x+2)

x(x−2)

×

x−2

3x+6

=

x+2

x−2

×

x−2

3x+6

=

(x+2)(x−2)

(x−2)(3x+6)

=

x+2

3x+6

=

x+2

3(x+2)

=3

Therefore, the value of (x2−2x/x2+2x)*(3x+6/x−2) is