Question

value of x²+y² when value of x-y =3 x-y=28​

Answer 1

Answer:

x² + y² = 65

Step-by-step explanation:

If x-y = 3, and xy = 28, what will be the value of (x^2+y^2)?

x-y = 3 … (1)

xy = 28 … (2)

From (1) x= y+3. Put that in (2) to get

y(y+3) = 28, or

y^2 + 3y = 28, or

y^2 + 3y - 28 = 0, or

(y+7)(y-4) = 0.

Hence y = -7 or +4, Then the corresponding values of x are -4 or 7.

Therefore (x^2+y^2) = (-4)^2+(-7)^2 = 16+49 = 65.

Answer = 65.

Answer 2

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Answer:

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