value of y in the quadratic equation 2y^2+11y+15=0 *
Answers
Answered by
21
Answer:
2y² + 11y + 15 = 0
2y² + (5+6)y + 15 = 0
2y² + 5y + 6y + 15 = 0
y(2y + 5) + 3(2y + 5) = 0
(y+3) (2y+5) = 0
y + 3 = 0
y = -3
2y + 5 = 0
2y = -5
y = -5/2
PLEASE MARK IT BRAINILIEST
And follow me for more qualitative answers.........✌
#Be Brainly With Neha..........❤
Similar questions
Accountancy,
4 months ago
History,
4 months ago
Math,
4 months ago
Math,
9 months ago
Math,
9 months ago
Computer Science,
1 year ago
Science,
1 year ago