Math, asked by sonawaleanita73, 9 months ago

value of y in the quadratic equation 2y^2+11y+15=0 *​

Answers

Answered by Anonymous
21

Answer:

2y² + 11y + 15 = 0

2y² + (5+6)y + 15 = 0

2y² + 5y + 6y + 15 = 0

y(2y + 5) + 3(2y + 5) = 0

(y+3) (2y+5) = 0

y + 3 = 0

y = -3

2y + 5 = 0

2y = -5

y = -5/2

PLEASE MARK IT BRAINILIEST

And follow me for more qualitative answers.........

#Be Brainly With Neha..........

Similar questions