Value of y is twice that of x and thrice that of z.If z=2,find the value of (2x-y+z)^3
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Y=2x =3z
z=2
Therefore (2x-y+z)^3=?
Ans:
Y=3*2=6
X=y/2=6/2=3
(2x-y+z)^3 = (2*3-6+2)^3
= (6-6+2)^3
= 2^3 = 8
z=2
Therefore (2x-y+z)^3=?
Ans:
Y=3*2=6
X=y/2=6/2=3
(2x-y+z)^3 = (2*3-6+2)^3
= (6-6+2)^3
= 2^3 = 8
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