Question

value of y which the distance between the points 2,-3 and 10,y is 10​

Answer 1

Answer:

y=3

Step-by-step explanation:

(10-2)²+(y+3)²=100

104-40+y²+9+6y=100

27=y²+6y

0=y²+6y-27

0=y²+9y-3y-27

y=3-9

as the distance can't be negative

Answer 2

Answer:

Answer of y is 3,-9

Step-by-step explanation:

10 = √(2-10)^2 +√(-3-y)^2

10 = √(-8)^2 + √(9+y^2+6y)

10 = √64 + √(9+y^2+6y)

Squaring both sides

100 = 64 + 9+y^2+6y

100-64-9 = y^2+6y

y^2+6y+27 = 0

y^2+9y-3y+27 = 0

y(y+9)+3(y+9) = 0

(y-3)(y+9) = 0

y = -9 and y = 3