Value the benefits of an informed choice of SHS track and strand
Answers
Answered by
3
Answer:
ANSWER
M = 2.50 kg
T = 200 N
l = 20.0 m
Mass per unit length, μ=M/l=2.50/20=0.125Kgm
−1
The velocity (v) of the transverse wave in the string is given by the relation:
v=
T/μ
=
200/0.125
=
1600
=40 m/s
∴ Time taken by the disturbance to reach the other end,
t=l/v=20/40=0.5s
Similar questions