Math, asked by ARYA527, 9 months ago

Value/ values of p for which the given equation has equal roots is/ are 2x^2-px+p=0

Answers

Answered by shivika2705
3

Answer:

0 and 8

Step-by-step explanation:

for equal roots D should be greater than 0.

therefore , in equation 2x²-px+p

let a=2 , b=-p , c= p

D=0

b²-4ac=0

(-p)²-4×2×p=0

p²-8p=0

p(p-8)=0

p=0,8

hence , these two are the values of p for which the given equation will have equal roots.

Answered by samyaknahar2438
0

Step-by-step explanation:

answer is 0 and 8

solving the equation we get

factors and then values can be there

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