Value/ values of p for which the given equation has equal roots is/ are 2x^2-px+p=0
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Answered by
3
Answer:
0 and 8
Step-by-step explanation:
for equal roots D should be greater than 0.
therefore , in equation 2x²-px+p
let a=2 , b=-p , c= p
D=0
b²-4ac=0
(-p)²-4×2×p=0
p²-8p=0
p(p-8)=0
p=0,8
hence , these two are the values of p for which the given equation will have equal roots.
Answered by
0
Step-by-step explanation:
answer is 0 and 8
solving the equation we get
factors and then values can be there
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