Math, asked by riya18kashyap, 6 months ago

values of k for which the
quadratic eq. qu? 2x+Kx+k=0
has equal root is
a.0 only
b. 4
c.8 only
d. 0,8​

Answers

Answered by itsbrainlybiswa
8

Answer:Compare given Quadratic equation 2x²-kx+k=0 with ax²+bx+c=0, we get

a = 2,b = -k , c = k,

Discreminant (D)=0

[ Given roots are equal ]

=> b²-4ac=0

=> (-k)²-4×2×k=0

=> k²-8k=0

=> k(k-8)=0

=> k = 0 or k=8

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Answered by Anonymous
1

Answer:

option D

Step-by-step explanation:

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