values of k for which the
quadratic eq. qu? 2x+Kx+k=0
has equal root is
a.0 only
b. 4
c.8 only
d. 0,8
Answers
Answered by
8
Answer:Compare given Quadratic equation 2x²-kx+k=0 with ax²+bx+c=0, we get
a = 2,b = -k , c = k,
Discreminant (D)=0
[ Given roots are equal ]
=> b²-4ac=0
=> (-k)²-4×2×k=0
=> k²-8k=0
=> k(k-8)=0
=> k = 0 or k=8
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Answered by
1
Answer:
option D
Step-by-step explanation:
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