Values of x y and z. Asap pls
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since ab=ac
therefore, angle abc= angle acb
angle abc +bca +cab=180°
abc+bca=180-52=128°
x=128/2=64°
angle abc=angle bca=64°
angle abd+angle abc=180°
abd + 64=180°
abd=180-64=116°
since AB = BD
therefore, angle dab= angle bda
angle abd+ bda + dab=180°
116+bda+dab=180°
bda+dab=180-116=64
y=z=64/2=32
therefore, angle abc= angle acb
angle abc +bca +cab=180°
abc+bca=180-52=128°
x=128/2=64°
angle abc=angle bca=64°
angle abd+angle abc=180°
abd + 64=180°
abd=180-64=116°
since AB = BD
therefore, angle dab= angle bda
angle abd+ bda + dab=180°
116+bda+dab=180°
bda+dab=180-116=64
y=z=64/2=32
Tomboyish44:
Thank you soooooooooo much!
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