Question

⦁ valuIf x – 2 is a factor of x3 – 2px2+px – 2, then find the e p.

Answer 1

Hey friend,

Here is the solution :-

$here \: x - 2 = 0 \\ x = 2 \\ \\ now \: put \: x = 2 \: in \: the \: given \: polynomial : - \\ \\ {x}^{3} - 2p {x}^{2} + px - 2 = 0 \\ \\ ({2})^{3} - 2p(2)^{2} + p(2) - 2 = 0 \\ \\ 8 - 2p(4) + p(2) - 2 = 0 \\ \\ 8 - 8p + 2p - 2 = 0 \\ \\ 8 - 6p - 2 = 0 \\ \\ 6 - 6p = 0 \\ \\ 6 = 6p \\ \\ p = \frac{6}{6} \\ \\ p = 1$

Here we get p = 1.

✨I hope this will help you....✨