Question

valur of (sin27+sin90+sin 45)×sin94

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Answer 1

sin27+sin90+sin45) sin94

sin27 = sin(45-18)

= sin45 cos18 - cos45 sin18

= sin45( cos18 - sin18)

both sin45 and cos45= 1/√2

= sin45( cos18-sin18+1) + 1) sin94

cos18 = √((5+√5))/2

sin18 = -1+√5)/4

=1/√2. ( √((5+√5)/2 ) +( 1 - √5)/4 + 1) sin94

= 1/4√2 ( 2√2 ( √(5 +√5) + 1- √5) + 4) sin94

= √( 5 +√5)/2 + (1- √5)/4√2. + 1/√2 ) sin94

take sin94 as sin90 its approximately 1 only

= √( 5 +√5)/2. + ( 1-√5)/4√2. + 1/√2

Answer 2

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